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6 | 6 | * @author Unknown |
7 | 7 | * |
8 | 8 | */ |
9 | | -class DecimalToBinary |
10 | | -{ |
11 | | - /** |
12 | | - * Main Method |
13 | | - * |
14 | | - * @param args Command Line Arguments |
15 | | - */ |
16 | | - public static void main(String args[]) |
17 | | - { |
18 | | - Scanner sc=new Scanner(System.in); |
19 | | - int n,k,s=0,c=0,d; |
20 | | - System.out.print("Decimal number: "); |
21 | | - n=sc.nextInt(); |
22 | | - k=n; |
23 | | - while(k!=0) |
24 | | - { |
25 | | - d=k%2; |
26 | | - s=s+d*(int)Math.pow(10,c++); |
27 | | - k/=2; |
28 | | - }//converting decimal to binary |
29 | | - System.out.println("Binary equivalent:"+s); |
30 | | - sc.close(); |
31 | | - } |
| 9 | +class DecimalToBinary { |
| 10 | + |
| 11 | + /** |
| 12 | + * Main Method |
| 13 | + * |
| 14 | + * @param args Command Line Arguments |
| 15 | + */ |
| 16 | + public static void main(String args[]) { |
| 17 | + conventionalConversion(); |
| 18 | + bitwiseConversion(); |
| 19 | + } |
| 20 | + |
| 21 | + /** |
| 22 | + * This method converts a decimal number |
| 23 | + * to a binary number using a conventional |
| 24 | + * algorithm. |
| 25 | + */ |
| 26 | + public static void conventionalConversion() { |
| 27 | + int n, b = 0, c = 0, d; |
| 28 | + Scanner input = new Scanner(System.in); |
| 29 | + System.out.printf("Conventional conversion.\n\tEnter the decimal number: "); |
| 30 | + n = input.nextInt(); |
| 31 | + while (n != 0) { |
| 32 | + d = n % 2; |
| 33 | + b = b + d * (int) Math.pow(10, c++); |
| 34 | + n /= 2; |
| 35 | + } //converting decimal to binary |
| 36 | + System.out.println("\tBinary number: " + b); |
| 37 | + } |
| 38 | + |
| 39 | + /** |
| 40 | + * This method converts a decimal number |
| 41 | + * to a binary number using a bitwise |
| 42 | + * algorithm |
| 43 | + */ |
| 44 | + public static void bitwiseConversion() { |
| 45 | + int n, b = 0, c = 0, d; |
| 46 | + Scanner input = new Scanner(System.in); |
| 47 | + System.out.printf("Bitwise conversion.\n\tEnter the decimal number: "); |
| 48 | + n = input.nextInt(); |
| 49 | + while (n != 0) { |
| 50 | + d = (n & 1); |
| 51 | + b += d * (int) Math.pow(10, c++); |
| 52 | + n >>= 1; |
| 53 | + } |
| 54 | + System.out.println("\tBinary number: " + b); |
| 55 | + } |
| 56 | + |
32 | 57 | } |
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